62 lines
1.9 KiB
C++
62 lines
1.9 KiB
C++
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// Lab 5 - summation.cpp
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// This program displays a series of terms and computes its sum.
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// Llewellyn van der Merwe
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#include <iostream>
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#include <cmath>
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using namespace std;
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int main()
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{
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// print out my name only once
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cout << "Llewellyn. \n";
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// Add do again option
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char doAgain = 'y';
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while (doAgain == 'Y' || doAgain == 'y')
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{
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int denom, // Denominator of a particular term
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term = 1, // Term counter
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finalTerm = 6; // The final term
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double sum = 0.0; // Accumulator that adds up all terms in the series
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// get the final term
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while (true)
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{
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cout << "Give us the number of terms: ";
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cin >> finalTerm;
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if(cin.fail() || finalTerm < 2 || finalTerm > 10) {
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cin.clear(); cin.ignore();
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cout << "\nMust be a number from 2 to 10" << endl;
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} else break;
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}
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// WRITE THE CODE TO START A FOR LOOP THAT LOOPS ONCE FOR EACH TERM.
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// I.E., FOR TERMS WITH DENOMINATORS FROM 2 TO THE FINAL DENOMINATOR.
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while (term <= finalTerm)
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{
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// calculate the denom
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denom = pow(2, term);
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// WRITE THE CODE TO PRINT THIS TERM.
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cout << "1/" << denom;
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if (finalTerm == term){
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// IF IT IS THE LAST TERM, FOLLOW IT WITH A =.
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cout << " = ";
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} else {
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// IF IT IS NOT THE LAST TERM, FOLLOW IT WITH A +.
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cout << " + ";
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}
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// WRITE THE CODE TO ADD THE VALUE OF THIS TERM TO THE ACCUMULATOR.
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sum += (double) 1 / denom;
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// increment the term counter
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term++;
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}
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// WRITE A LINE OF CODE TO PRINT THE SUM.
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cout << sum;
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// check if we are done
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cout << "\n\nDo you want to compute another series? (y/n) ";
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cin >> doAgain;
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}
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return 0;
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}
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