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Reduce overhead of debug calls if no log is enabled
In case no debug log is configured, then calls to debug.Log only incur the costs to check a single boolean flag making the call really cheap.
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parent
1823b8195c
commit
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@ -17,9 +17,10 @@ import (
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)
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)
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var opts struct {
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var opts struct {
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logger *log.Logger
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isEnabled bool
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funcs map[string]bool
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logger *log.Logger
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files map[string]bool
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funcs map[string]bool
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files map[string]bool
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}
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}
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// make sure that all the initialization happens before the init() functions
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// make sure that all the initialization happens before the init() functions
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@ -30,6 +31,12 @@ func initDebug() bool {
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initDebugLogger()
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initDebugLogger()
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initDebugTags()
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initDebugTags()
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if opts.logger == nil && len(opts.funcs) == 0 && len(opts.files) == 0 {
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opts.isEnabled = false
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return false
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}
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opts.isEnabled = true
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fmt.Fprintf(os.Stderr, "debug enabled\n")
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fmt.Fprintf(os.Stderr, "debug enabled\n")
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return true
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return true
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@ -173,6 +180,10 @@ func checkFilter(filter map[string]bool, key string) bool {
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// Log prints a message to the debug log (if debug is enabled).
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// Log prints a message to the debug log (if debug is enabled).
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func Log(f string, args ...interface{}) {
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func Log(f string, args ...interface{}) {
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if !opts.isEnabled {
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return
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}
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fn, dir, file, line := getPosition()
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fn, dir, file, line := getPosition()
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goroutine := goroutineNum()
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goroutine := goroutineNum()
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