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Set decimal base for converting subseconds to int
The leading 0 triggers an automatic conversion as an octal value. This fails because it is a decimal value. Setting the base to 10 prevents this automatism and treats the value as a decimal value. Fixes: [WAN] string_util.cpp:cvt_strtoofft(96): something error is occurred in convert std::string(017080564) to off_t, thus return 0 as default. Related to #1676
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@ -45,7 +45,7 @@ static struct timespec cvt_string_to_time(const char *str)
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strmtime = str;
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std::string::size_type pos = strmtime.find('.', 0);
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if(std::string::npos != pos){
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nsec = cvt_strtoofft(strmtime.substr(pos + 1).c_str());
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nsec = cvt_strtoofft(strmtime.substr(pos + 1).c_str(), 10);
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strmtime.erase(pos);
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}
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}
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